We first claim that v 1 = v 7 v 7 ) is a cycle C. It has no chord by Lemma ?? (ii), so C 2 = G 2 [S]. Moreover, p S (v i ) ? 4 if i is even and p S (v i ) ? 3 otherwise. C 2 is a cycle+triangle graph, thus, by Theorem ??, it is 3-choosable and so p S -choosable. This contradicts Lemma ??. Let w 1 (resp. w 7 ) be the neighbour of v 1 (resp. w 7 ) distinct from v 2 (resp. v 6 ) and for i ? {2, 4, 6}, let w i be the neighbour of v i not in {v i?1 , v i+1 }. Let W = {w 1, (ii), w 2 = v 4 and w 6 = v 4 and by Lemma ?? (iii), w 1 = v 4 and w 7 = v 4 ,
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