The transition t 0 has the own eect (b, R) deleting (b, g) which clearly is not needed in the rest of P + (s); it has the side eect f g = 1 deleting f g = 0 which clearly is not needed in the rest of P + (s) Thus the oDG + -relevant deletes of t 0 are P + >0 (s)-recoverable. In case (b), similarly we can reorder P + (s) so that either (1) pickup(g, b, L) is the rst operator in P + (s), or (2) its only predecessor is move(R, L). The transition t 0 has the own eect (b, g) deleting (b, L) which clearly is not needed in the rest of P + (s) It has the side eect f g = 0 deleting f g = 1, that latter fact may be needed by other pickup operators in P + (s) ,
which are applicable after board(l, c); drop(g, b, R) recovers f g = 1. Thus, again, the oDG + -relevant deletes of t 0 are P + >0 (s)-recoverable. Hence, in both cases, we can apply Theorem 2. cost d * (oDG + ) = 1 in cases (a1) and (b1), so there we get the bound 0, ro) = 2 in cases (a2) and (b2) so there we get the bound 1 ,
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