then there is another hole which size is more than 2, it is a contradiction If the destination of P in Alg1 is to B1 and the size of B1 is equal to 1, then B1 moves to B0, the size of B2 is 2, and the robot ,
after R joins B0, then new destination of P is to B0 by both of Alg1 and Alg2, Therefore, the system achieves the gathering in O(k 2 ) rounds ,
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